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DBWR will be writing these modified blocks back out to disk at some point in the future (actually, since the table doesn t fit into the cache, we know that DBWR has already written out at least some of them!) Now, if I run the query again ops$tkyte%ORA11GR2> exec :redo := get_stat_val( 'redo size' ); PL/SQL procedure successfully completed ops$tkyte%ORA11GR2> declare 2 l_rec t%rowtype; 3 begin 4 for i in 1 . 10000 5 loop 6 select * into l_rec from t where id=i; 7 end loop; 8 end; 9 / PL/SQL procedure successfully completed ops$tkyte%ORA11GR2> exec dbms_outputput_line( (get_stat_val('redo size')-:redo) || ' bytes of redo generated..'); 0 bytes of redo generated.. PL/SQL procedure successfully completed I see that no redo is generated the blocks are all clean.

If we were to rerun the preceding example with the buffer cache set to hold a little more than 100,000 blocks, we d find that we generate little to no redo on any of the SELECTs we will not have to clean dirty blocks during either of our SELECT statements This is because the10,000-plus (remember the index was modified as well) blocks we modified fit comfortably into 10 percent of our buffer cache, and we are the only users There is no one else mucking around with the data, and no one else is causing our.

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data to be flushed to disk or accessing those blocks In a live system, it would be normal for at least some of the blocks to not be cleaned out sometimes This behavior will most affect you after a large INSERT (as just demonstrated), UPDATE, or DELETE one that affects many blocks in the database (anything more than 10 percent of the size of the cache will definitely do it) You ll notice that the first query to touch the block after this will generate a little redo and dirty the block, possibly causing it to be rewritten if DBWR had already flushed it or the instance had been shut down, clearing out the buffer cache altogether There is not too much you can do about it It is normal and to be expected.

Note Not all the code for UndoableBase is listed in this book. I cover only the key parts of the algorithm. For the rest of the code, refer to the download at www.apress.com/book/view/1430210192 or www.lhotka.net/ cslanet/download.aspx.

If Oracle didn t do this deferred cleanout of a block, a COMMIT could take as long to process as the transaction itself The COMMIT would have to revisit each and every block, possibly reading them in from disk again (they could have been flushed) If you are not aware of block cleanouts and how they work, they will be one of those mysterious things that just seem to happen for no reason For example, say you UPDATE a lot of data and COMMIT Now you run a query against that data to verify the results The query appears to generate tons of write I/O and redo It seems impossible if you are unaware of block cleanouts; it was to me the first time I saw it.

You go and get someone to observe this behavior with you, but it is not reproducible as the blocks are now clean on the second query You simply write it off as one of those database mysteries a mystery that only happens when you are alone In an OLTP system, you ll probably never see a block cleanout happening, since those systems are characterized by small, short transactions that affect only a few blocks By design, all or most of the transactions are short and sweet Modify a couple of blocks and they all get cleaned out In a warehouse where you make massive UPDATEs to the data after a load, block cleanouts may be a factor in your design Some operations will create data on clean blocks For example, CREATE TABLE AS SELECT, direct-path loaded data, and direct-path inserted data will all create clean blocks.

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